E299：Bulls and Cows（字符串處理）

You are playing the following?Bulls and Cows?game with your friend: You write down a number and ask your friend to guess what the number is. Each time your friend makes a guess, you provide a hint that indicates how many digits in said guess match your secret number exactly in both digit and position (called "bulls") and how many digits match the secret number but locate in the wrong position (called "cows"). Your friend will use successive guesses and hints to eventually derive the secret number.

For example:

Secret number:  "1807"
Friend's guess: "7810"

Hint:?1?bull and?3?cows. (The bull is?8, the cows are?0,?1?and?7.)

Write a function to return a hint according to the secret number and friend's guess, use?A?to indicate the bulls and?B?to indicate the cows. In the above example, your function should return?"1A3B".

Please note that both secret number and friend's guess may contain duplicate digits, for example:

Secret number:  "1123"
Friend's guess: "0111"

In this case, the 1st?1?in friend's guess is a bull, the 2nd or 3rd?1?is a cow, and your function should return?"1A1B".

You may assume that the secret number and your friend's guess only contain digits, and their lengths are always equal.

大意就是給兩個(gè)字符串，輸出兩個(gè)參數(shù)：

① 在兩個(gè)字符串中位置相同且數(shù)值相等的數(shù)字的個(gè)數(shù)?

② 除了①的匹配外，兩個(gè)字符串?dāng)?shù)值相等但是位置不相同的其他數(shù)字個(gè)數(shù)

public String getHint(String secret, String guess) {
        	
        	HashMap s=new HashMap();//用兩個(gè)HashMap分別存儲(chǔ)兩個(gè)字符串的字符
        	HashMap g=new HashMap();
        	int a=0;//a記錄①條件的數(shù)值
        	int b=0;//b記錄②條件的數(shù)值
        	for(int i=0;i